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7x^2-65x+48=0
a = 7; b = -65; c = +48;
Δ = b2-4ac
Δ = -652-4·7·48
Δ = 2881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-\sqrt{2881}}{2*7}=\frac{65-\sqrt{2881}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+\sqrt{2881}}{2*7}=\frac{65+\sqrt{2881}}{14} $
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